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15a^2+26a+7=0
a = 15; b = 26; c = +7;
Δ = b2-4ac
Δ = 262-4·15·7
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-16}{2*15}=\frac{-42}{30} =-1+2/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+16}{2*15}=\frac{-10}{30} =-1/3 $
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